Starter 1: Daily 10 – 3 x tables - DIVISION
check your answers at the bottom of the page.
Starter 3: What is a quotient?
Today we’ll be halving two and three digit numbers!
Look at the model below.
It is showing halving 6 ones, then 6 tens and finally 6 hundreds using base-10 equipment (the dienes). This is ‘sharing’ into two groups.
Now draw your model (the dienes) showing 50 made up of 5 tens and 500 made up of 5 hundreds. Decide how you would halve 50 and 500 (=share into two groups).
10, 30, 50, 70 and 90 are odd multiples of ten and, therefore, 1 ten will need regrouping. This results in a quotient ending in 5. Likewise, odd multiples of a hundred will result in a regrouped hundred and quotients that will end in 50.
The answer to a division problem is the quotient.
Now try these for a little more practice:
1. 24 ÷ 2 and 240 ÷ 2.
2. 124 ÷ 2
3. (See picture below)
Now try these for your main task today:
Draw dienes to solve division problems.
Can you use the cherry model (circles) / part-whole model to solve these division problems as well? See this handy method below
Today I would like you to give your own opinion about these two poems and write 2 short paragraphs summarising each one and another paragraph giving your opinion about which one you prefer.
Read the two poems from yesterday again to remind you of each one.
Your first task today is to summarise what both poems are about with a short paragraph for each.
Your summaries should:
You may use your work from yesterday to remind you quickly about the poems.
Your Second task today is to write a paragraph giving your opinion about which poem you prefer and explain why.
Read these example reviews below if you are stuck or want to see what yours may look like once you have finished.
Listen to and read the poems then try having a go at activity 1 today.
We will be trying the other activities later this week.
Maths starter 2 answers:
1. 9 2. 7 3. 9 4. 8 5. 6 6. 6
Maths extra practice answers:
24 ÷ 2 = 12
240 ÷ 2 = 120
2. 124 ÷ 2 = 62
3. 50 ÷ 2 = 25
Eric should regroup the ten he hasn’t shared yet into ones and then share ten ones into two groups. This results in a quotient ending in 5.